How to calculate big powers, 1.09^90..plz help asap..

How to calculate big powers, 1.09^90..plz help asap..

 

X=1.09^90log x= log(1.09)^90=90log(1.09)=90log (109/100)=90(log109-log100)X=antilog (90 (log109-log100))

 

* one ,= second ,* third,=fourth,....... *23rd ,=24th

 

I don't have log table so answer can't be calculated here.The way to look log ; antilog table is different.

 

In exams calculator is not allowed. So you must know how to use logarithm table.

 

Wont get power 90 question tomorrow for sure... How evr. If need be.. calc me 1.9*1.9===89times.

 

Enter 1.09 in simple calc then press x once,then press = for 11 times,dn press x twice nd den = for 9 times ,u'll get the answer as 90=10x9